x^2+5,5x=146

Solution for x^2+5,5x=146 equation:

x^2+5.5x=146

We move all terms to the left:

x^2+5.5x-(146)=0

a = 1; b = 5.5; c = -146;
Δ = b2-4ac
Δ = 5.52-4·1·(-146)
Δ = 614.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.5)-\sqrt{614.25}}{2*1}=\frac{-5.5-\sqrt{614.25}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.5)+\sqrt{614.25}}{2*1}=\frac{-5.5+\sqrt{614.25}}{2}
$